The half-life of Palladium-100 is 4 days. After 12 days a sample of Palladium-100 has been reduced to a mass of 7 mg.
Answers
Answered by
5
Answer:
Here is your answer
Let
T = 4 days be the half-life,
t be time elapsed, e.g., 12 days or 4 weeks,
m(t) be the mass after time t.
The general formula is
m(t) = m(0)2-t/T
If you prefer to think in terms of the example,
then 12 days (being 3 times the half-time) caused
3 halving of the initial quantity;
that is, reducing the initial quantity by a factor of 8.
To answer the first problem
2mg = m(0)2-12/4
m(0) = 2mg x 8 = 16mg
To answer the second question
m(28) = 16mg x 2-28/4= 16 mg x 2-7 = 0.125mg
Answered by
1
Answer:
Hi!
Hi! PLEASE F.O.LL.OW ME.
Similar questions