Question

$\mathbb{ \ \ Q\ U\ E\ S\ T\ I\ O\ N\: \: }$

The half-life of Palladium-100 is 4 days. After 12 days a sample of Palladium-100 has been reduced to a mass of 7 mg.​

Answer 1

Answer:

Here is your answer

Let

T = 4 days be the half-life,

t be time elapsed, e.g., 12 days or 4 weeks,

m(t) be the mass after time t.

The general formula is

m(t) = m(0)2-t/T

If you prefer to think in terms of the example,

then 12 days (being 3 times the half-time) caused

3 halving of the initial quantity;

that is, reducing the initial quantity by a factor of 8.

To answer the first problem

2mg = m(0)2-12/4

m(0) = 2mg x 8 = 16mg

To answer the second question

m(28) = 16mg x 2-28/4= 16 mg x 2-7 = 0.125mg

Answer 2

Answer:

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