Math, asked by vihaan80, 11 months ago


 \mathfrak{hey \: there \:  ! } \:

\mathbf{ CBSC \:  } \: class \: 10 \: chapter  \cdot\: 2 \: \:  polynomials


 \sim \: answer  \: to \:  get  \: the \:  brainliest \:  \sim

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Answered by Anonymous
0

Heya!!

Let the two zeros of given quadratic polynomial be a and b

It is given that a = - b

a + b = - ( 8 - 8k ) / 4

- b + b = - ( 8 - 8k ) /4

8 - 8k = 0

k = 1

TO FIND ZEROS OF kx² + 3kx + 2 put value of k here we get

x² + 3x + 2

Let it's zeros be c and d

c + d = -3 and c × d = 2

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