Question

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what torque acts on a 40 turn coil of 100 cm² area carring a current of 10 A held with its axis at right angle to a uniform magnetic fieldof 0.2 T?
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Answer 1

Answer:

400

Explanation:

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Answer 2

Answer:

From given data,

Area of coil (A)=40×30×10

−4

=0.12 m

2

Number of turns (N)=100

Current in coil (I)=10A

Magnetic field (B)=5T at an angle θ=30

o

So torque on the coil:

τ=NBIAcosθ [from τ=MBcosθ,M=NIA]

=100×5×10×0.12×cos(30

o

)

τ≃520N−m