Question

$\mathscr\red{HI}$


Questions of the Day.

Solve both please...



1. The velocity of a particle of mass 150 g changes from 8m/s to 12m/s in 2 seconds.Assuming that a constant force acts on it Find the magnitude of the force ..

2. A force of 4.0 n acts on a body of mass 2.0 kg for 4.0 s. Assuming the body to be initially at rest , FIND

a . its velocity when the force stops acting ,

b. the distance covered in 10 s after the force starts acting ..


Answer of 1. is 0.30 N.
Answer of 2. is a - 8m/s
b- 64 m



FULL SOLUTION PLEASE.
NO SPAMMING.


$\mathscr\green{THANKS}$​

Answer 1

Answer:

Force = mass × acceleration.

acceleration = change in velocity / time.

a = 12-8/ 2 = 2 m/s

m = 150 g = 0.15 kg.

since u have to convert all to S.I units or c.gs units.

i am doing it in s.i. units.

force = 0.15 × 2 kg m/s

force = 0.3 N..

Answer 2

Explanation:

Refer to the attachment.