Math, asked by Anonymous, 2 months ago


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Construct a rhombus whose diagonals are 6cm and 4.2 cm long.




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Answers

Answered by Anonymous
2

Answer:

hope, this will help you

Step-by-step explanation:

Draw a line segment (say) bd of length 6 cm and draw it's perpendicular bisector xy.

Bd intersects ac at o.

Now with o as center and radius = 2cm draw arcs on both the sides.

The arcs cut xy at a and c.

Join b to a , a to d , d to c and c to a.

Abcd is your required rhombus

Answered by JasmineSelvia38
1

Answer:

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Step-by-step explanation:

Steps of Construction:

1) Draw a line segment say AC = 4 cm

2) With A as centre draw an arc of length equal to half of 6cm ie., 3 cm below AC

3) With C as centre draw another arc with same radius such that it intersects the previous arc. Mark the intersection point as B

4) Join points A, B and points B, C

5) Repeat the same process on other side of AC

Thus rhombus ABCD will be obtained

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