Question

${n}^{2} - 1$
-is divisible by 8, if n is
(a) an integer
(b) a natural number
(c) an odd integer
(d) an even integer​

Answer 1

Answer:

c

Step-by-step explanation:

it is answer of your questions

${3}^{2} - 1 = 8$

Answer 2

Let n = 2m + 1, any odd integer

⇒ n² = (2m + 1)² = 4m² + 4m + 1 = 2 ⇒n² - 1 4m(m + 1) =

And we know that, the product of any two consecutive integer is an even integer

so we can assume m(m+1) 2p, for some integer p -

:: n². 1 4m (2p) = 8p, which is clearly multiple of 8

kyu?, aapne nahi pada?

Lol, xD

Hope it helps ya...