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Answers
Answer :-
→ Actual price of the tea set = ₹ 100
→ Actual price of the lemon set = ₹ 80
Explanation :-
Let the CP of the tea set be ₹ x and CP of the lemon set be ₹ y .
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Now, according to the given conditions of the question :-
⇒ 15y/100 - 5x/100 = 7
⇒ 3y/20 - x/20 = 7
⇒ (3y - x)/20 = 7
⇒ 3y - x = 7(20)
⇒ 3y - x = 140 ----(1)
Also :-
⇒ 5x/100 + 10y/100 = 13
⇒ x/20 + y/10 = 13
⇒ (x + 2y)/20 = 13
⇒ x + 2y = 20(13)
⇒ x + 2y = 260 ----(2)
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Now, we can solve eq.1 and eq.2 to obtain our answer.
Adding eq.1 and eq.2 we get :-
⇒ 3y - x + x + 2y = 260 + 140
⇒ 5y = 400
⇒ y = 400/5
⇒ y = 80
Putting value of 'y' in eq.1 :-
⇒ 3(80) - x = 140
⇒ 240 - x = 140
⇒ x = 240 - 140
⇒ x = 100
Solution :-
Let the cost of tea set be x and lemon set be y
5% of x
5/100 × x
5x/100
15% of y
15/100 × y
15y/100
Now
15y/100 - 5x/100 = 7
15y - 5x/100 = 7
15y - 5x = 100 × 7
15y - 5x = 700
Now
5% of x
5/100 × x
5x/100
10% of y
10/100 × y
10y/100
5x/100 + 10y/100 = 13
5x + 10y/100 = 13
5x + 10y = 13 × 100
5x + 10y = 1300
15y - 5x + 5x + 10y = 1300 + 700
15y + 10y = 2000
25y = 2000
y = 2000/25
y = 80
By using 1
15(80) - 5x = 700
1200 - 5x = 700
-5x = 700 - 1200
-5x = -500
x = 500/5
x = 100