Question

$one \: of \: the \: factors \: of \: a ^{3} (b - c) ^{3} + b ^{3} (c - a)^{3} + c ^{3} (a - b) ^{3} is$
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Answer 1

Answer:

$one \: of \: the \: factors \: of \: a ^{3} (b - c) ^{3} + b ^{3} (c - a)^{3} + c ^{3} (a - b) ^{3} is$

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Answer 2

Answer:

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Now ((a2 + b2 + c2) + k (ab + bc + ca) ) (a+b+c) = a3+b3+c3−3abc. The value of can be easily found out to be -1 (even by simply multiplying and comparing); hence the other factor, (a2 + b2 + c2 - ab - bc - ca) . Thus a3+b3+c3−3abc = (a2 + b2 + c2 - ab - bc - ca) (a+b+c)