Question

${p}^{2} + \frac{1}{p {}^{2} } = 0$
prove that
$p {}^{8} - 40 \sqrt{6} - 1 = 0$
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Answer 1

Answer:

Your question is erroneous

Step-by-step explanation:

Sum of two positive number only can be zero if bot number are zero and p and 1/p can't be zero together .