Question

${p}^{2} \: {q}^{2} \: {r}^{2} \: \div \: pqr$

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Answer 1

Answer:

the answer is 0

Step-by-step explanation:

$(p2-q2r)2+2p2q2r$

$=2p^2-2q^2r+2p^2q^2r$

$=2p^2(-2q^2r+2q^2r)$

$=2p^2 * 0$

$=0(ANSWER)$

or u can see the attachment

                                    by Jennie