Question

${p}^{2} {x}^{2} + ( {p}^{2} - {q}^{2} )x - {q}^{2} = 0$
solve for x

Answer 1

I hope it is not wrong and helps you frnd

Answer 2

p²x + (p² - q²)x - q²

=> p²x + p²x - q²x - q²

=> p²x(x + 1) - q²(x + 1)

=> (p²x - q²)(x + 1)

=> x = -1

and,

x = q²/p²