Question

$p^{5}-p^{4}+p^{2}$​

Answer 1

Answer:

1/p in positive and in negative p-¹

Step-by-step explanation:

Given:-

p⁵-p⁴+p²

To find:-

The answer

Solution:-

According to Bodmas rule, First there will be addition.

$p⁵-p⁴+p² \\ {p}^{5} - {p}^{4 + 2} \\ {p}^{5} - {p}^{6} \\ {p}^{ - 1}$

By using,

${a}^{ - m} = \frac{1}{ {a}^{1} }$

$\frac{1}{p}$