x=1
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p (x)=x^3+x^2-3x-3
x=1
p (1)=(1)^3+(1)^2-3 (1)-3
= 1+1-3-3
=-4
p (1)=-4
x=1
p (1)=(1)^3+(1)^2-3 (1)-3
= 1+1-3-3
=-4
p (1)=-4
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