Question

$p(x) = x {}^{3} - x {}^{2} + x$
then find the value of 1/2 {p(-1) + p(1)}

Answer 1

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Answer 2

Hlw mate

(p+1)x-(2p+3)y-1=0
x = 2
y = 3


(p+1)x-(2p+3)y-1=0
px + x -( 2py +3y)  -1 =0
px + x -2py - 3y -1= 0
putting the value of x and y 
p(2) + 2 - 2p(3) - 3(3) -1 = 0
2p  +2 -6p  -9  -1 = 0
-4p  - 8 = 0
-4p = 8
p = -2


Hope it helps u