Question

$p = )y) = y = 2 - y + 1$
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Answer 1

Answer:

Find p(0), p(1) and p(2) for each of the following polynomials: (i) p(y) = y2 – y + 1 Given p(y) = y2 – y + 1 Putting y = 0 p(0) = (0)2 – 0 + 1 = 0 – 0 + 1 = 1 Putting y ...

Answer 2

Answer:

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