Question

$\pi = 3.14$
Circumference of circle = 37.2
Find the
Diameter of circle =

Solution needed
Step by step
If anyone wants to solve hanwritten so,handwriting should be proper so,that I can understand. ​

Answer 1

given:

Circumference = 37.2 units

$\pi = 3.14$

formula :

$circumference = 2\pi \: r$

where, r is the radius

$2\pi \times r = 37.2 \\ \\ 2 \times 3.14 \times r = 37.2 \\ \\ 6.98 \times r = 37.2 \\ \\ r = \frac{37.2}{6.98} \\ \\ r = \frac{18.6}{3.49}$

We know that

2r = diameter

let the diameter be d

$d = 2 \times \frac{18.6}{3.49 } \\ \\ d = 10.6$

d=10.6 units

Answer 2

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

$\tt \pi = 3.14$

$\tt Circumference\: of\: circle = 37.2$

$\tt Find\: the$

$\tt Diameter\: of\: circle$

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

$\sf \bf {\boxed {\mathbb {GIVEN}}}$

• $\sf \bf \pi = 3.14$
• $\sf \bf Circumference\: of\: circle = 37.2$

$\sf \bf {\boxed {\mathbb {TO\:FIND}}}$

• $\sf \bf Diameter\: of\: circle$

$\sf \bf {\boxed {\mathbb {SOLUTION}}}$

${\boxed{\boxed{\boxed{\color{blue}{\sf \bf C=2 \pi r}}}}}$

• $\sf \bf C=circumference\: of\: circle$
• $\sf \bf \pi=3. 14$
• $\sf \bf r=radius\:of\:circle$

$\tt \underline{\color{orange} {Substitute \:the \:values}}$

$\sf \bf \implies 37.2=2 \times 3.14 \times r$

$\sf \bf \implies 37.2=6.28 \times r$

$\sf \bf \implies r= \dfrac{37.2}{6.28}$

$\implies{\boxed {\color{purple} {\sf \bf r=5.92}}}$

-----------------------------------------------------------

${\boxed {\boxed{\boxed {\color {blue} {\sf \bf d=2 r}}}}}$

• $\sf \bf d=diameter\: of\: circle$
• $\sf \bf r=radius\:of\:circle$

$\tt \underline{\color{orange} {Substitute \:the \:values}}$

$\sf \bf \implies d=2 \times 5.92$

$\implies{\boxed{\boxed{\color{green} {\sf \bf d=11.84}}}}$

$\therefore{\underbrace {\tt The\:diameter\:of\:the\:circle\:is\:11.84}}$

$\sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

__________________________________________

$\sf \bf\huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$

$\sf \bf Circumference\:of\:the\:circle =2 \pi r$

$\sf \bf Area\:of\:the\:circle = \pi {r}^{2}$

$\sf \bf Diameter\:of\:the\:circle = 2 r$

$\sf \bf Radius\:of\:the\:circle = \sqrt{\dfrac{A}{\pi}}$

${\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5070}}}}}}}}}}}}}}}$