Question

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CLASS : 8th


SUBJECT : MATHEMATICS


$<b><u>QUESTION :</b></u>$

FACTORISE using Middle term breaking :-

a) 6x² + 11x - 10
b) (a+b)² - 11(a+b) - 42
c) (x-2y)² - 6(x-2y) + 5

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Answer 1

(a)

Given Equation is 6x^2 + 11x - 10

⇒ 6x^2 - 4x + 15x - 10

⇒ 2x(3x - 2) + 5(3x - 2)

⇒ (2x + 5)(3x - 2).

(b)

Given Equation is (a + b)^2 - 11(a + b) - 42

⇒ (a + b)^2 - 14(a + b) + 3(a + b) - 42

⇒ (a + b)[a + b - 14] + 3[a + b - 14]

⇒ (a + b + 3)(a + b - 14)

(c)

Given Equation is (x - 2y)^2 - 6(x - 2y) + 5

⇒ (x - 2y)^2 - 5(x - 2y) - (x - 2y) + 5

⇒ (x - 2y)[x - 2y - 5] - (x - 2y - 5)

⇒ (x - 2y - 1)(x - 2y - 5).

Hope this helps!

Answer 2

Answer:

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