Question

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Answer 1

Answer:

40^a=2 implies log base40 2

Similarly, 40^b=2 implies log base40 2

10 raise to the power 1-a-b/2(1-b)

Substituting a, b=log base40 2, we get

10 raise to the power 1-log base40 2-log base40 2/2(1-log base40 2)

=10 raise to the power 1-2log base40 2/2-2log base40 2

Putting 1 as log base40 40 to make the bases equal so that we can apply the rule, we get

=10 raise to the power log base40 40-2log base40 2/2*log base40 40-2log base40 2

Applying the rule: log base a x-log base a y=log base a x/log base a y

=10 raise to the power log base40 40/2log base40 2/2 log base40 40/2 log base40 2

=10 raise to the power log base40 40/2log base40 2*2 log base40 2/2 log base40 40

Now log base40 40 gets canceled out with log base40 40 and 2log base40 2 also gets canceled out with 2 log base40 2. Remaining is:

10 raise to the power 1/2= root 10=3.162

Hope it will help you

Mark the brainliest