Question

$\pink{Help \:me}$Please help me in this question

________________________

solve the following equation and verify ur answer​

Answer 1

ur answer in this attachment I hope it's help u.....

Answer 2

$\huge= > \frac{x + b}{a - b} = \frac{x - b}{a + b} \\ \\ \large = > (x + b)(a - b) = (x - b)(a + b) \\ \\ \large = > \: \: \cancel{ax} - bx + ab - \cancel{{b}^{2} } = \cancel{ax} + bx - ab - \cancel{{b}^{2} } \\ \\\huge = > \: \: \: \: ab + ab = bx + bx \\ \\ \huge = > \: \: \: \: \: \cancel2a\cancel{b} = \cancel2\cancel{b}x \\ \\ \huge = > \: \: \: \: \: a = x$

Thus,

• Value of x is a

Putting the value of x, we get,

$= > \frac{a + b}{a - b} = \frac{a - b}{a + b} \: \: \: \: \: \: \: \: \rm\cdots(i) \\ \\ \huge = > {(a + b)}^{\cancel2} = {(a - b)}^{ \cancel2} \\ \\ \\ \huge = > \cancel{a} + b = \cancel{a} - b \\ \\ \huge= > b + b = 0 \\ \\ \huge = > 2b = 0 \\ \\ \huge = > b = 0$

Putting the value of b in Equation (i), we get,

$= > \frac{a + b}{a - b} = \frac{a - b}{a + b} \\ \\ \\ \huge= > \frac{a + 0}{a - 0} = \frac{a - 0}{a + 0} \\ \\ \\ \huge= > \: \: \: \: \: \: \frac{a}{a} = \frac{a}{a} \\ \\ \huge = > \: \: \: \: \: 1 = 1$

Since,

• On putting the respective value of x & b, we get, LHS = RHS, thus, the equation verifies.