Question

$\pink{too \: hard}$

If A and B are two events and P (A) = 2/3, P(B) =3/5, P(AUB) = 5/6, then the value of P(A¹/B¹) =

$● \: \frac{5}{12}$
$● \: \frac{2}{14}$
$● \: \frac{9}{12}$
$● \: \frac{12}{5}$
$\pink{no \: copy \: answer} \\ \pink{only \: type \: answer}$
​

Answer 1

Step-by-step explanation:

P(A

′

∩B

′

)=1−P(A∪B)

=1−[P(A)+P(B)−P(A∩B)]

=1−[

5

3

+

9

4

−

5

3

×

9

4

] [P(A∩B)=P(A)⋅P(B)]

=1−[

45

27+20−12

]=1−

45

35

=

45

10

=

9

2