![\pink{too \: hard} \pink{too \: hard}](https://tex.z-dn.net/?f=%5Cpink%7Btoo+%5C%3A+hard%7D)
If A and B are two events and P (A) = 2/3, P(B) =3/5, P(AUB) = 5/6, then the value of P(A¹/B¹) =
![● \frac{5}{12} ● \frac{5}{12}](https://tex.z-dn.net/?f=%E2%97%8F+%5Cfrac%7B5%7D%7B12%7D)
![● \frac{12}{5} ● \frac{12}{5}](https://tex.z-dn.net/?f=%E2%97%8F+%5Cfrac%7B12%7D%7B5%7D)
![● \frac{5}{13} ● \frac{5}{13}](https://tex.z-dn.net/?f=%E2%97%8F+%5Cfrac%7B5%7D%7B13%7D)
![● \frac{13}{5} ● \frac{13}{5}](https://tex.z-dn.net/?f=%E2%97%8F+%5Cfrac%7B13%7D%7B5%7D)
![\pink{no \: spam \: no \: copy \: answer} \pink{no \: spam \: no \: copy \: answer}](https://tex.z-dn.net/?f=%5Cpink%7Bno+%5C%3A+spam+%5C%3A+no+%5C%3A+copy+%5C%3A+answer%7D)
Answers
Answered by
1
Answer:
5 upon 12 is correct that helps you
please mark as brain list
Answered by
1
Answer:
5/12
Step-by-step explanation:
Here, A and B are two events.
P(A)=2/3 , P(B)=3/5 , P(A U B)=5
We know that, P(A/B)= P(A ∩ B) /P(B)
So, P(A'/B')= P(A' ∩ B') /P(B')
=>P(A' ∩ B')
= 1-P(A U B)
= 1-(5/6)
=(6-5)/6
= 1/6
=>P(B')
= 1-P(B)
= 1-3/5
=(5-3)/5
= 2/5
=>P(A'/B')
=(1/6) /(2/5)
= (1×5) /(6×2)
= 5/12
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