Question

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Answer 1

Solution:-

Given equation is

$\implies\sf{\left[\begin{array}{c c c}4 & -2 \\ 4 & 0\end{array}\right] + 3A = \left[\begin{array}{c c c}-2 & -2 \\ 1 & -3\end{array}\right]}$

We have to find the value of A

$\sf \implies3A =\sf{\left[\begin{array}{c c c} - 2 & -2 \\ 1 & - 3\end{array}\right]} - {\left[\begin{array}{c c c}4 & -2 \\ 4 & 0\end{array}\right]}$

Now we can write as

$\sf \implies3A =\sf{\left[\begin{array}{c c c} - 2 & -2 \\ 1 & - 3\end{array}\right]} + {\left[\begin{array}{c c c} - 4 & + 2 \\ - 4 & 0\end{array}\right]}$

Now

$\sf \implies3A =\sf{\left[\begin{array}{c c c} - 6 & 0 \\ - 3 & - 3\end{array}\right]}$

$\sf \implies \: A =\sf{\left[\begin{array}{c c c} \dfrac{ - 6}{3} & & 0 \\ \\ \dfrac{ - 3}{3} & & \dfrac{ - 3}{3} \end{array}\right]}$

$\sf \implies A =\sf{\left[\begin{array}{c c c} - 2 & 0 \\ - 1 & - 1\end{array}\right]}$

Answer

$\sf \implies A =\sf{\left[\begin{array}{c c c} - 2 & 0 \\ - 1 & - 1\end{array}\right]}$

Answer 2

Didi your Answer is in this attachment ⬆️