Math, asked by subhashattri07, 3 months ago

$please \: \: solve \: \: the \: \: question \: ..$

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Answered by krish171817

1

Step-by-step explanation:

Determinant of A =

${cos}^{2} \alpha \: + \: {sin}^{2} \alpha$

= 1

Therefore A^-1 exists.

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