Question

$pls \: do \: ans \: my \\ \\ question \: very \: eeded$
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Answer 1

Answer:

Percentage of Metal A = 33.32%

Percentage of Metal B = 24.99%

Percentage of Metal C = 41.66%

Step-by-step explanation:

here, Let the ratio constant be = $x$

now, $4x + 3x + 5x = 250$

     = $12x = 250$

     = $x = \frac{250}{12}$

     = $x = 20.83$

so, Weigh of Metal A = 4 × 20.83 = 83.32 g

Weigh of Metal B = 3 × 20.83 = 62.49 g

Weigh of Metal C = 5 × 20.83 = 104.15 g

∴ Percentage of Metal A = $\frac{83.32 g}{250 g} * 100$  = 33.32%

  Percentage of Metal B = $\frac{62.49 g}{250 g} * 100$  = 24.99%

  Percentage of Metal C = $\frac{104.15 g}{250 g} * 100$  = 41.66%

hope it will help you.

Answer 2

Step-by-step explanation:

A:B:C=4:3:5

let take a constant "k"

4k+3k+5k=250

12k=250

k=250/12=125/6

then mass of A=4x125/6=500/6

then mass of B=3x125/6=125/2

then mass of C=5x125/6=625/6

$\sf{percentage\:of\:any\:particle = \frac{mass\:of\:particle}{mass ofcompound} \times 100 }$

$\sf{percentage\:of\:massA = \frac{ \frac{500}{6} }{250} \times 100\rightarrow \frac{100}{3}percentage }$

$\sf{percentage\:of\:massB = \frac{ \frac{125}{2} }{250} \times 100\rightarrow25 percentage }$

$\sf{percentage\:of\:massC = \frac{ \frac{625}{6} }{250} \times 100 = \frac{5}{12} \times 100 = 500/12 }$