![pq(p + 3) + r \: for \: p = 2 \: q = 3 and r = - 1 pq(p + 3) + r \: for \: p = 2 \: q = 3 and r = - 1](https://tex.z-dn.net/?f=pq%28p+%2B+3%29+%2B+r+%5C%3A+for++%5C%3A+p+%3D+2+%5C%3A+q+%3D+3+and+r+%3D++-+1)
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Hey there!
Given,
pq( p + 3) + r
here,
p = 2q , q = 3 , r = -1
p = 2 * 3 = 6
Now,
pq ( p + 3) + r
= 6*3 (6+3) - 1
= 6 * 3 * 9 - 1
= 162 - 1
= 161
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