Question

$prove \: that \: 3 + \sqrt{5} \: is \: an \: irrational \: number$
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Answer 1

Step-by-step explanation:

3+√5is rational

(3+√5]=a/b

√5=a/b-3

√5=a-2b/b

a,b is integer

so,3+√5is irrational

Answer 2

Answer:

Let's assume 3+√5 is a rational number 3+√5= a/b

√5=a/b - 3

√5=a/b - 3b/b

√5= a-3b/b

as we know that √5 is an irrational number.

so, a-3b/b is also as irrational number.

Therefore, our assumption is wrong.

Hence, 3+√5 is an irrational number.

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Step-by-step explanation:

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