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Answer:
heya mate...
There u go :
Given: √5
We need to prove that √5 is irrational
Proof:
Proof:Let us assume that √5 is a rational number.
So it can be expressed in the form p/q where p,q are co-prime integers and q≠0
it can be expressed in the form p/q where p,q are co-prime integers and q≠0⇒√5=p/q
On squaring both the sides we get,
On squaring both the sides we get,⇒5=p²/q²
On squaring both the sides we get,⇒5=p²/q² ⇒5q²=p² —————–(i)
On squaring both the sides we get,⇒5=p²/q² ⇒5q²=p² —————–(i)p²/5= q²
So 5 divides p
So 5 divides pp is a multiple of 5
So 5 divides pp is a multiple of 5⇒p=5m
So 5 divides pp is a multiple of 5⇒p=5m⇒p²=25m² ————-(ii)
From equations (i) and (ii), we get,
From equations (i) and (ii), we get,5q²=25m²
From equations (i) and (ii), we get,5q²=25m²⇒q²=5m²
From equations (i) and (ii), we get,5q²=25m²⇒q²=5m²⇒q² is a multiple of 5
From equations (i) and (ii), we get,5q²=25m²⇒q²=5m²⇒q² is a multiple of 5⇒q is a multiple of 5
Hence, p,q have a common factor 5. This contradicts our assumption that they are co-primes. Therefore, p/q is not a rational number
Hence, p,q have a common factor 5. This contradicts our assumption that they are co-primes. Therefore, p/q is not a rational number√5 is an irrational number
Hence proved .
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hope it helps you dear.......
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