![prove \: that\sqrt[3]{2} \: is \: a \: rational \: number](https://tex.z-dn.net/?f=+prove+%5C%3A+that%5Csqrt%5B3%5D%7B2%7D++%5C%3A+is+%5C%3A+a+%5C%3A+rational+%5C%3A+number "prove \: that\sqrt[3]{2} \: is \: a \: rational \: number")
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Answer:
cube root of two is not rational it is irrational
Step-by-step explanation:
cube root 2 cant be written in p/q form thats why
it is irrational
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