Math, asked by singhanmol599126, 8 months ago


prove \: that \:  \sqrt{ - 4 +  \sqrt{8 + 16 { \csc }^{4} \alpha  \times  { \sin}^{4}  \alpha  = 2 \csc( \alpha ) -  \sin( \alpha )   } }
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Answered by priyankakumari7
0

Answer:

$$\begin{lgathered}\sqrt{ 4 + \sqrt{8 + 16 \csc( { \alpha }^{4}) \sin( { \alpha }^{4} ) } } \\ = \sqrt{ 4 + \sqrt{8 + 16 \times \frac{1}{ \sin( { \alpha }^{4} ) } \times \sin( { \alpha }^{4} ) } } \\ = \sqrt{4 + \sqrt{8 + 1} } \\ = \sqrt{4 + \sqrt{9} } \\ = \sqrt{4 + 3} \\ = \sqrt{7} \\ = 2.64575 \: (approximately)\end{lgathered}$$

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