Math, asked by Anonymous, 2 months ago


prove \: that \:  \sqrt{5} \:  is \: irrational
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Answers

Answered by sdirector7
4

Answer:

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Answered by lensleopard458
3

Step-by-step explanation:

Let 5 be a rational number.

then it must be in form of  qp  where,  q=0     ( p and q are co-prime)

5=qp

5×q=p

Suaring on both sides,

5q2=p2           --------------(1)

p2 is divisible by 5.

So, p is divisible by 5.

p=5c

Suaring on both sides,

p2=25c2         --------------(2)

Put p2 in eqn.(1)

5q2=25(c)2

q2=5c2

So, q is divisible by 5.

.

Thus p and q have a common factor of 5.

So, there is a contradiction as per our assumption.

We have assumed p and q are co-prime but here they a common factor of 5.

The above statement contradicts our assumption.

Therefore, 5 is an irrational number.

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