Question

$prove \: that \\ {(x + y) }^{2} = {x}^{2} + {y}^{2} + 2xy$
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Answer 1

$\huge{\mathcal{\blue{\underline{Answer}}}}$

$(x + y) { }^{2} = (x + y)(x + y) \\ = x {}^{2} + x y + xy + y {}^{2} \\ = x {}^{2} + 2xy + y {}^{2}$

Answer 2

Step-by-step explanation:

We have

( x + y )²

We can write it as

( x + y )( x + y )

opening the brackets

x ( x + y ) + y ( x + y )

x² + xy + yx + y²

which is x² + y² + 2xy = RHS

Hence proved

#answerwithquality #BAL