Math, asked by hellynpatel06, 3 months ago


prove \: this \: \:  \sqrt{1 + sin \: a \div 1 - sin \: a}  = sec \: a + tan \: a

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Answers

Answered by Rupeshsir
1

Answer:

The second and third identities can be obtained by manipulating the first. The identity

1

+

cot

2

θ

=

csc

2

θ

is found by rewriting the left side of the equation in terms of sine and cosine.

Prove:

1

+

cot

2

θ

=

csc

2

θ

1

+

cot

2

θ

=

(

1

+

cos

2

θ

sin

2

θ

)

Rewrite the left side

.

=

(

sin

2

θ

sin

2

θ

)

+

(

cos

2

θ

sin

2

θ

)

Write both terms with the common denominator

.

=

sin

2

θ

+

cos

2

θ

sin

2

θ

=

1

sin

2

θ

=

csc

2

θ

Similarly,

1

+

tan

2

θ

=

sec

2

θ

can be obtained by rewriting the left side of this identity in terms of sine and cosine. This gives

1

+

tan

2

θ

=

1

+

(

sin

θ

cos

θ

)

2

Rewrite left side

.

=

(

cos

θ

cos

θ

)

2

+

(

sin

θ

cos

θ

)

2

Write both terms with the common denominator

.

=

cos

2

θ

+

sin

2

θ

cos

2

θ

=

1

cos

2

θ

=

sec

2

θ

The next set of fundamental identities is the set of even-odd identities. The even-odd identities relate the value of a trigonometric function at a given angle to the value of the function at the opposite angle and determine whether the identity is odd or even.

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