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here's your answer in the given attachment
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Given that:
- A man is standing at a level of 10 m above the water.
- Angle of elevation of elevation of the top of hill is 60° .
- Angle of depression of the foot of hill is 30° .
To Find:
- Distance of hill from the ship and height of the hill.
Formula used:
- tan30° = 1/√3
- tan60° = √3
Solution:
Let the distance of the ship from the hill be x.
So, tan30° = 10/x
x = 10 √3 m....(1)
Now, Let the original height of the ship be h.
So, Again Using the above formula, we have
tan60° = (h-10)/x
√3 = (h-10)/10√3
30 = h - 10
h = 40 m.
So, height of the hill is 40 m and distance of the ship from base is 10√3 m.
[Refer to the attachment for diagram]
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