Question

$q(y) = 27y - 4y + \sqrt{11 \: } \: at \: y = 3$​

Answer 1

$\huge \underline {{ \green {\mathbb{QUESTION}}}}$

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$\LARGE\tt \orange {q(y) = 27y - 4y + \sqrt{11 \: } \: at \: y = 3}$

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$\huge \underline { {\blue {\mathbb{ANSWER}}}}$

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$\large\pink {\implies \tt \: q(y) \: = \: 27y \: - 4y \: + \sqrt{11} }$

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$\Large\purple { \sf Put \: y = 3}$

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$\large\pink{ \to \tt \: q(3) \: = 27(3) - 4(3) + \sqrt{11} }$

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$\large\pink{ \tt \to \: q(3) = 69 \: + 3.31 \: ( \because\sqrt{11} \approx \: 3.31)}$

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$\Large\red {\to \tt \: q(3) = 72.31}$

‎$\huge{ \green{\boxed{\underline{☆тɦαɳҡร☆}}}}$

Answer 2

Answer:

⟹q(y)=27y−4y+

11

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\Large\purple { \sf Put \: y = 3}Puty=3

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\large\pink{ \to \tt \: q(3) \: = 27(3) - 4(3) + \sqrt{11} }→q(3)=27(3)−4(3)+

11

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\large\pink{ \tt \to \: q(3) = 69 \: + 3.31 \: ( \because\sqrt{11} \approx \: 3.31)}→q(3)=69+3.31(∵

11

≈3.31)

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\Large\red {\to \tt \: q(3) = 72.31}→q(3)=72.31