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The population of a town increases by 10.5 °/• every year. If it present population is 7,95,600, what was it a year ago?

❤❤please solve its urgent ......❤❤

It is percentage unit .......so solve it.... ​

Answer 1

$\red{\text{\underline{\underline{Answer:}}}}$

$\green{\therefore {\text{Population\:one\:year\:ago=7,20,000}}}$

$\blue{\text{\underline{\underline{Step-by-step\:explanation:}}}}$

$\underline \bold{Given : } \\ \implies \text{Increase \% = 10.5 \%} \\ \\ \implies \text{Present \: population = 7,95,600 } \\ \\ \underline \bold{To \: Find: } \\ \red{\implies {\text{Population \: 1 \: year \: ago =?}}}$

• According to given question :

$\text{Let \: previous \: year \: population = x} \\ \\ \bold{Increased \: population} \\ \implies Increase = 10.5 \% \: of \: x \\ \\ \implies Increase = \frac{10.5}{100} \times x \\ \\ \implies \text{Increase = 0.105x} \\ \\ \green{\implies {\text{Population \: of \: next \: year= x + 0.105x}}} \\ \\ \green{\implies { \text{ Population \:of \: next \: year =1.105x}}} \\ \\ \implies 1.021x = 7,95,600 \\ \\ \implies x = \frac{ \cancel{7,95,600}}{ \cancel{1.105}} \\ \\ \green{\implies \text{x = 7,20,000}} \\ \\ \green{\therefore \text{Population\: 1 \: year \: ago = 7,20,000}}$

Answer 2

$\huge\red{♡Answer♡}$

Ok, I solve it in percentage...

This is like a simple interest on a principal amount....

Population of town increased= 10.5 %

present population of a town= 7,95,600

Let, Popular of village of 1 year is x

p×(1+10.5%)=795,600

P= 795,600/1.105=720,000

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