Question

$question:$

find the simple interest on rupees 20000 for four years 10% p.a. simple interest​..
​

Answer 1

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{darkblue}{Given:}}}}}}}\end{gathered}$

$\dashrightarrow\sf{Principle = 20000}$

$\dashrightarrow\sf{Rate = 10 \%}$

$\dashrightarrow{\sf{Time = 4 \: years}}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{blue}{To Find:}}}}}}}\end{gathered}$

• Simple Interest

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{darkblue}{Using Formula:}}}}}}}\end{gathered}$

$\dag\underline{\boxed{\sf{S.I = \bigg\{\dfrac{P \times R \times T}{100}\bigg\}}}}</p><p>\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{blue}{Solution:}}}}}}}\end{gathered}$

$\quad { \implies{\sf{S.I = \bf\bigg(\dfrac{P \times R \times T}{100}\bigg)}}}$

• Substitute the values..

$\quad {\implies{\sf{S.I = \bf\bigg(\dfrac{20000 \times 10 \times 4}{100}\bigg)}}}$

$\quad { \implies{\sf{S.I = \bf\bigg(\dfrac{200{\cancel{00}} \times 10 \times 4}{\cancel{100}}\bigg)}}}$

$\quad { \implies{\sf{S.I = \bf{200 \times 10 \times 4}}}}$

$\quad {\implies{\sf{S.I = \bf{8000}}}}$

$\begin{gathered} \dag{\overline{\underline{\boxed{\textsf{\textbf{\color{red}{S.I = Rs.8000}}}}}}}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{pink}{Learn More:}}}}}}}\end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered} \bigstar \underline \purple{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc} {\sf{Amount = Principle + Interest}} \\ \\ \sf{ P=Amount - Interest }\\ \\ \sf{ S.I = \dfrac{P \times R \times T}{100}} \\ \\ \sf{P = \dfrac{Interest \times 100 }{Time \times Rate}} \\ \\ \sf{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}$

Answer 2

Answer:

$\red\bigstar$ Given

• $\leadsto$ Principle = Rs20000
• $\leadsto$ Time = 4 years
• $\leadsto$ Rate = 10%

$\begin{gathered}\end{gathered}$

$\red\bigstar$ To Find

• $\leadsto$ Simple Interest

$\begin{gathered}\end{gathered}$

$\red\bigstar$ Using Formula

$\dashrightarrow{\sf{S.I = \bigg(\dfrac{P \times R \times T}{100}\bigg)}} \begin{gathered}\end{gathered}$

Where

• $\leadsto$ S.I donates Simple Interest
• $\leadsto$ P donates Principle
• $\leadsto$ R donates Rate of Interest
• $\leadsto$ T donates Time

$\begin{gathered}\end{gathered}$

$\red\bigstar$ Solution

$\dashrightarrow{\sf{S.I = \bigg(\dfrac{20000 \times 10 \times 4}{100}\bigg)}} \begin{gathered}\end{gathered}$

$\dashrightarrow{\sf{S.I = \bigg(\dfrac{20000 \times 40}{100}\bigg)}} \begin{gathered}\end{gathered}$

$\dashrightarrow{\sf{S.I = \bigg(\dfrac{800000}{100}\bigg)}} \begin{gathered}\end{gathered}$

$\dashrightarrow{\sf{S.I = \bigg( \cancel\dfrac{800000}{100}\bigg)}} \begin{gathered}\end{gathered}$

$\dashrightarrow{\sf{S.I = \bigg({8000}\bigg)}} \begin{gathered}\end{gathered}$

$\dashrightarrow{\underline{\boxed{\sf{S.I = {Rs.8000}}}}} \begin{gathered}\end{gathered}$

∴ The Simple Interest is Rs.8000

$\begin{gathered}\end{gathered}$

$\red\bigstar$ Additional Information

$\dashrightarrow{\sf{ P = \dfrac{100 \times S. I}{R \times T }}}$

$\dashrightarrow{\sf{ R = \dfrac{100 \times S. I}{P \times T}}}$

$\dashrightarrow{\sf{ T = \dfrac{100 \times I}{P \times R }}}$

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