Question

$QUESTION$

Solve the QuEStiON in the following attachment fast



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Answer 1

Answer:

$Area \: of \: trapezium \: = \frac{1}{2} (ad \: + bc \: ) \times ab$

$24.5 = \frac{1}{2} (10 + 4) \times 4$

$h = 3.5cm$

$Area \: of \: quadrant \: ABE \: = \frac{90°}{360°} \times \pi(3.5) {}^{2} sq.m$

$= 9.625sq.m$

$Area \: of \: shaded \: region \: = 24.5 - 9.625 \\ = 14.875sq.m$

Answer 2

$\star\:\:\:\sf\large\underline\blue{Question:-}$

• Solve the question given in the attachment.

$\star\:\:\:\sf\large\underline\blue{Solution:-}$

Here,

AD=BC=10cm.

AB=?

Area = 24.5cm²

Or,

24.5 = 1/2 * (10+4)*AB

Or,

AB=24.5/7=3.5cm.

Area of quadrant ABE

=90/360 * π * 3.5^2 cm²

=9.625cm²

Therefore, area of the shaded region

=24.5-9.625cm²

=14.875cm²