Question

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$If \:one\: root\:is \:reciprocal \:of \\other \:of\: a \quadratic \: equation \\10x^{2}+kx+p = 0 \:then \:find \:p$​

Answer 1

Hey there!

Given Equation,

10x² + kx + p = 0

Standard Quadratic Equation is given as:

ax² + bx + c

here,

a = 10 , b = k , c = p.

Product of roots = c / a

i.e p / 10.

According to Question,

Roots are reciprocal to each other. i.e if one root is x then other root is 1/x. So, we will always get the product as 1.

Similarly,  p/10 = 1

or, p = 10

Answer 2

Answer:

Hey mate here's your answer

P-10....

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