A chord of a circle of radius 7 cm subtends an angle of 120°™at the centre of the circle .
Find the length of the chord.
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BC (CHORD)IS EQUAL TO 7ROOT3 CMS
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Answer:
7√3
Step-by-step explanation:
- given: radius=7cm ,∠ BAC =120° , to prove : length of chord BC . proof : In triangle ABD, Sin60° = BD/AB =√3/2=BD/7 ,2BD=7√3 ∴BD= 7√3 . But, BD =- 1/2 BC (∵ AD intersect BC ) , ∴ 2BD =BC ,∴ 2 * 7√3/2 = BC , ∴BC =7/√3
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