If √x = secA + tanA and
√y = secA - tanA then write it in single linear equation.
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Sec^2A - tan^A = 1
(SecA-tanA)(secA+tanA)=1 (a^2 - b^2) = (a-b)(a+b)
(X^1/2)(Y^1/2)=1 (^1/2= square root)
XY^1/2=1
XY=1
(SecA-tanA)(secA+tanA)=1 (a^2 - b^2) = (a-b)(a+b)
(X^1/2)(Y^1/2)=1 (^1/2= square root)
XY^1/2=1
XY=1
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Answer:
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hope thus helps u out thcx for asking me this question I enjoyed answering it !!!!!!!
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