Math, asked by PRATHAMABD, 11 months ago

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\yellow{Please Solve _/\_}
Express the HCF of 462 and 222 as 468x + 222y where x , y are integers in two different ways​

Answers

Answered by Anonymous
2

462 = 222 × 2 + 18

222 = 18 × 12 + 6

18 = 6 × 3 + 0

H.C.F = 6

6 = 222 - 18 × 12

6 = 222 - ( 462 - 222 × 2 ) × 12

6 = 222 - 462 + 222 × 2 × 12

6 = 222 × 3 - 462 × 12

6 = 222 × 3 + 462 × -12

x = -12 , and y = 3

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