Physics, asked by Anonymous, 6 months ago


 \red{\Huge{\underline{\underline{\frak{Question : }}}}}
For a PlanoConvex lens, prove that focal length is always equal from both the surfaces of the lens. (Derivation)
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Answered by Ekaro
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Introduction : (Thin Lens)

A thin lens is called convex if it is thicker at the middle and it is called concave if it is thicker at the ends.

One surface of a convex lens is always convex. Depending on the surface a convex lens is categorised as

  • Biconvex or convexo convex, if the other surface is also convex.
  • Plano convex if the other surface is plane.
  • Concavo convex is the other surface is concave.

Similarly concave lens is categorised as concavo-concave or biconcave, plano-concave and convexo-concave.

Formula :

For a spherical, thin lens having the same medium on both sides :

\bigstar\:\underline{\boxed{\bf{\purple{\dfrac{1}{f}=(n-1)\bigg(\dfrac{1}{R_1}-\dfrac{1}{R_2}\bigg)}}}}

Where R₁ and R₂ are x coordinate of the centre of curvature of the 1st surface and 2nd surface respectively.

Remember :

  • Radius of curvature/focal length of concave mirror is taken negative and that for convex mirror is taken positive.
  • Radius of curvature or focal length of plane mirror = ∞

Case - I :

  • Surface 1 : convex mirror
  • Surface 2 : plane morror

:\implies\tt\:\dfrac{1}{f}=(n-1)\bigg(\dfrac{1}{R_1}-\dfrac{1}{R_2}\bigg)

  • R₁ = + R and R₂ = ∞

:\implies\tt\:\dfrac{1}{f}=(n-1)\bigg(\dfrac{1}{R}-\dfrac{1}{\infty}\bigg)

:\implies\tt\:\dfrac{1}{f}=(n-1)\bigg(\dfrac{1}{R}-0\bigg)

:\implies\tt\:\dfrac{1}{f}=(n-1)\bigg(\dfrac{1}{R}\bigg)

:\implies\bf\:f=\dfrac{R}{(n-1)}\:\dots\:(1)

Case - 2 :

  • Surface 1 : plane mirror
  • Surface 2 : concave morror

:\implies\tt\:\dfrac{1}{f}=(n-1)\bigg(\dfrac{1}{R_1}-\dfrac{1}{R_2}\bigg)

  • R₁ = ∞ and R₂ = - R

:\implies\tt\:\dfrac{1}{f}=(n-1)\bigg(\dfrac{1}{\infty}-\dfrac{1}{-R}\bigg)

:\implies\tt\:\dfrac{1}{f}=(n-1)\bigg(0+\dfrac{1}{R}\bigg)

:\implies\tt\:\dfrac{1}{f}=(n-1)\bigg(\dfrac{1}{R}\bigg)

:\implies\bf\:f=\dfrac{R}{(n-1)}\:\dots\:(2)

Focal length in both cases are same!

Hence Proved!!

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