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Answered by
0
Hey
Here is your answer,
Tan (π/8) = Tan 45°
Tan 45° = 1
Hope it helps you!
Avanish010:
wrong
Answered by
7
Hey !!!
We know that ,
tanπ / 8 = tan22 ½
tan22½° = sin22½° /cos22½ °
squaring on both sides .
tan² 22½ = 2sin²22½ / 2 cos²22½
Or , we know that ,
cos2¢ = 1 - 2sin²¢
1 - cos2¢ = 2sin²¢ -----1)
and, also , cos2¢ = 2cos²¢ - 1
cos2¢ + 1 = 2cos²¢ ----2)
From 1st and 2nd equation .
tan²22½ = 1 - cos45° / 1 + cos45°
tan²22½ = √2 - 1 / √2 + 1
rationalise it .
√2 - 1 / √2 + 1 × √2 - 1 /√2 - 1 = ( √2 - 1)² / 1
tan²22 ½ = √2 - 1 ..
since , value of tanπ/10 = √2 - 1
_______________________
We know that ,
tanπ / 8 = tan22 ½
tan22½° = sin22½° /cos22½ °
squaring on both sides .
tan² 22½ = 2sin²22½ / 2 cos²22½
Or , we know that ,
cos2¢ = 1 - 2sin²¢
1 - cos2¢ = 2sin²¢ -----1)
and, also , cos2¢ = 2cos²¢ - 1
cos2¢ + 1 = 2cos²¢ ----2)
From 1st and 2nd equation .
tan²22½ = 1 - cos45° / 1 + cos45°
tan²22½ = √2 - 1 / √2 + 1
rationalise it .
√2 - 1 / √2 + 1 × √2 - 1 /√2 - 1 = ( √2 - 1)² / 1
tan²22 ½ = √2 - 1 ..
since , value of tanπ/10 = √2 - 1
_______________________
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