Question

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Find the length of a conductor which is moving with a speed of 10 meter per second in the direction perpendicular to the direction of magnetic field of induction 0.8 Tesla, if it induces an emf of 8V between the ends of the conductor.



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Answer 1

v = 10 m/s , B= 0.8T, v = 8 v ,e = 90^o ε = vbL sine - L = ɛ/ vb sino = L = 8/

10x0.8xsin90^o

L = 10 m

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Answer 2

Explanation:

given,

V=10m/s

B=0.8T

v=8 volt

e=90°

€=vbl-sine -L

=8/10*0.8* sin90°

=10

hope it helps...

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