Question

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Answer 1

Answer:

If the adjacent sides of a rectangle are $-6x^2 + 7x^2y^2 + xy$ and $7xy - 5x^2 + 9x^2y^2$ then its perimeter is $- 22x^2 + 32x^2y^2 + 16 xy$.

Step-by-step explanation:

Given:

Length$(l) = -6x^2 + 7x^2y^2 + xy$

Breadth $(b) =7xy - 5x^2 + 9x^2y^2$

Formula : Perimeter of rectangle$= 2l + 2b$

Perimeter of rectangle $= 2( -6x^2 + 7x^2y^2 + xy) + 2(7xy - 5x^2 + 9x^2y^2)$

=  $-12x^2 + 14x^2y^2 + 2 xy + 14xy - 10x^2 + 18x^2y^2$

$=-12x^2 - 10x^2 + 14x^2y^2 + 18x^2y^2 + 2 xy+ 14xy$

$= - 22x^2 + 32x^2y^2 + 16 xy$