Question

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Answer 1

Answer:

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2000kg/m³ is the required density of wood.

Explanation:

According to the Question

It is given that,

Mass,m = 144g

Piece of wood measures 4cm by 2cm by 9cm

we have to calculate the density of the wood.

As we know that density is calculated by the mass per unit volume.

Conversion of unit

Mass=144/1000 kg

Mass = 0.144 kg

Calculation of Volume

Volume of Piece of Wood = 4×2×9

→ Volume of Piece of Wood = 72 cm³

Conversion of unit

→ Volume of Piece of Wood = 72/1000000 m³

→ Volume of Piece of Wood = 7.2×10-5 m³

Now, calculating the density of wood.

d = m/v

by putting the value we get

→d = 0.144/7.2x10-5

→ d = 0.144×105/7.2

→d = 14400/7.2

→ d = 144000/72

→ d = 2000 kg/m³

• Hence, the density of the wood is 2000 kg/m³.

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Answer 2

Step-by-step explanation:

Given dimensions of the wood piece is : 4 cm by 2cm by 9 cm. = 0.04 m by 0.02 m by 0.09 m.

So volume of the given wood piece is (4*2*9) cubic centimetres. = 72 cc.

In SI units,volume is : (0.04*0.02*0.09)= (0.000072) metres cube.

Now , weight of the wood piece is : 144 grams = 0.144 kgs.

So, density is given by : mass/volume

Hence density of the given wood piece in SI units is = (0.144/0.000072) = 2000 kg/m^3.

Hope this will help you