Question

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Explain kirchhoff's laws with examples​

Answer 1

Answer:

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It states that the algebraic sum of all potential drops and emfs along any closed path in a network is zero. OR. The algebraic sum of the emfs in a loop of a circuit is equal to the algebraic sum of the product of current and resistances in it. Mathematically, the loop rule may be expressed as : ∑E=∑IR

Answer 2

Answer :-

Kirchhoff's Laws :-

i) Kirchoff's current Law ( Junction Law ) :

★ It states that " The algebraic sum of the currents meeting at a point of the circuit is zero."

★ Total current entering a junction is equal to total current leaving the junction.

$\dag \: \sf\Sigma \: I_{in} = \Sigma \: I_{out}$

★ It is based in law of conservation of charge.

★ Also known as KCL.

ii) Kirchoff's Voltage Law ( Loop Law ) :-

★ It states that " Algebraic sum of all potential difference along a closed loop is zero. "

$\dag \: \sf\Sigma \: V = 0$

★ It is based on conservation of energy

★ While transversing a loop if potential increases, put a positive sign in expression and if sign decreases put a negative sign.

Example -

( refer to the attachment )

In the above circuit, for V₁ the loop is going from positve to negative, so there will be negative sign for V₁.

Also for V₂, the loop is going from positve to negative, so it will have negative sign.

For V₃, it is going from negative to positve, hence it will have positive sign.

For V₄, the loop is going from positve to negative, so it will have negative sign.

Hence,

→ -V₁ - V₂ + V₃ - V₄ = 0