Question

$sameer \: purchased \: 3 \frac{1}{2} kg \: apples \: and \: 4 \frac{3}{4}kg \: oranges.what \: is \: the \: total \: weight \: of \: fruits \: purchased \: by \: her \: ?$
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Answer 1

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$total \: weight \: of \: the \: fruits \: purchased \: by \: the \: sameera \: is (\:3 \frac{1}{2} + 4 \frac{3}{4} )kg$

$\huge\underline\bold\orange{Now,}$

$3 \frac{1}{2} + 4 \frac{3}{4} \\ ⟹ \frac{7}{2} + \frac{19}{4} \\ ⟹ \frac{7 \times2}{2 \times 2} + \frac{19 \times 1}{4 \times 1} \\ ⟹\frac{14}{4} + \frac{19}{4} = \frac{14 + 19}{4} = \frac{33}{4} = 8 \frac{1}{4}$

$hence \: total \: weight \: is \: 8 \frac{1}{4} kg$

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${\huge{\underline{\small{\mathbb{\blue{HOPE\:HELP\:U\:BUDDY :)}}}}}}$

${\huge{\underline{\small{\mathbb{\pink{</p><p>~AngelicCandy♡ :)}}}}}}$

Answer 2

$\huge{\orange{\boxed{\fcolorbox{lime}{aqua}{\pink{ANSWER}}}}}$

• $\bf{Weight~of~apples~=~3~\dfrac{1}{2}~kg~}$

• $\bf{Weight~of~oranges~=~4~\dfrac{3}{4}~kg~}$

☕ Total weight,

$= \: 3 \times \frac{1}{2} + 4 \times \frac{3}{4} \\ \\ = \: \frac{7}{2} + \frac{19}{4} \\ \\ = \frac{14 + 19}{4} \\ \\ = \frac{33}{4}$

Since,

• Numerator > Denominator

☃️ Converting to mixed fraction,

• $\bf{8~\dfrac{1}{4}}$

∴ The total weight of fruits purchased by Sameer is $\bf{8~\dfrac{1}{4}~kg}$.