Question

$\sec( \alpha + \tan( \alpha ) ) \div \sec( \alpha - \tan( \alpha ) ) = 2 + \sqrt{3 \frac{2 - \sqrt{3} }{?} } } } }$
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Answer 1

Step-by-step explanation:

$\sec( \alpha + \tan( \alpha ) ) \div \sec( \alpha - \tan( \alpha ) ) = 2 + \sqrt{3 \frac{2 - \sqrt{3} }{?} } } } }$