Question

$\sec( \alpha ) + \tan( \alpha) = p \: show \: that \: p {?}^{2} - 1 \div p { + 1 = \sin( \alpha ) }^{2}$
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Answer 1

Step-by-step explanation:

make equations and solve the equations

use

${ \sec( \alpha ) }^{2} - { \tan( \alpha ) }^{2} = 1$